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-rw-r--r--gcc/config/h8300/lib1funcs.asm703
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diff --git a/gcc/config/h8300/lib1funcs.asm b/gcc/config/h8300/lib1funcs.asm
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-;; libgcc1 routines for the Hitachi h8/300 cpu.
-;; Contributed by Steve Chamberlain.
-;; sac@cygnus.com
-
-/* Copyright (C) 1994 Free Software Foundation, Inc.
-
-This file is free software; you can redistribute it and/or modify it
-under the terms of the GNU General Public License as published by the
-Free Software Foundation; either version 2, or (at your option) any
-later version.
-
-In addition to the permissions in the GNU General Public License, the
-Free Software Foundation gives you unlimited permission to link the
-compiled version of this file with other programs, and to distribute
-those programs without any restriction coming from the use of this
-file. (The General Public License restrictions do apply in other
-respects; for example, they cover modification of the file, and
-distribution when not linked into another program.)
-
-This file is distributed in the hope that it will be useful, but
-WITHOUT ANY WARRANTY; without even the implied warranty of
-MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
-General Public License for more details.
-
-You should have received a copy of the GNU General Public License
-along with this program; see the file COPYING. If not, write to
-the Free Software Foundation, 59 Temple Place - Suite 330,
-Boston, MA 02111-1307, USA. */
-
-/* As a special exception, if you link this library with other files,
- some of which are compiled with GCC, to produce an executable,
- this library does not by itself cause the resulting executable
- to be covered by the GNU General Public License.
- This exception does not however invalidate any other reasons why
- the executable file might be covered by the GNU General Public License. */
-
-/* Assembler register definitions. */
-
-#define A0 r0
-#define A0L r0l
-#define A0H r0h
-
-#define A1 r1
-#define A1L r1l
-#define A1H r1h
-
-#define A2 r2
-#define A2L r2l
-#define A2H r2h
-
-#define A3 r3
-#define A3L r3l
-#define A3H r3h
-
-#define S0 r4
-#define S0L r4l
-#define S0H r4h
-
-#define S1 r5
-#define S1L r5l
-#define S1H r5h
-
-#define S2 r6
-#define S2L r6l
-#define S2H r6h
-
-#ifdef __H8300__
-#define MOVP mov.w /* pointers are 16 bits */
-#define ADDP add.w
-#define CMPP cmp.w
-#define PUSHP push
-#define POPP pop
-
-#define A0P r0
-#define A1P r1
-#define A2P r2
-#define A3P r3
-#define S0P r4
-#define S1P r5
-#define S2P r6
-#endif
-
-#ifdef __H8300H__
-#define MOVP mov.l /* pointers are 32 bits */
-#define ADDP add.l
-#define CMPP cmp.l
-#define PUSHP push.l
-#define POPP pop.l
-
-#define A0P er0
-#define A1P er1
-#define A2P er2
-#define A3P er3
-#define S0P er4
-#define S1P er5
-#define S2P er6
-
-#define A0E e0
-#define A1E e1
-#define A2E e2
-#define A3E e3
-#endif
-
-#ifdef L_cmpsi2
-#ifdef __H8300__
- .section .text
- .align 2
- .global ___cmpsi2
-___cmpsi2:
- cmp.w A2,A0
- bne .L2
- cmp.w A3,A1
- bne .L2
- mov.w #1,A0
- rts
-.L2:
- cmp.w A0,A2
- bgt .L4
- bne .L3
- cmp.w A1,A3
- bls .L3
-.L4:
- sub.w A0,A0
- rts
-.L3:
- mov.w #2,A0
-.L5:
- rts
- .end
-#endif
-#endif /* L_cmpsi2 */
-
-#ifdef L_ucmpsi2
-#ifdef __H8300__
- .section .text
- .align 2
- .global ___ucmpsi2
-___ucmpsi2:
- cmp.w A2,A0
- bne .L2
- cmp.w A3,A1
- bne .L2
- mov.w #1,A0
- rts
-.L2:
- cmp.w A0,A2
- bhi .L4
- bne .L3
- cmp.w A1,A3
- bls .L3
-.L4:
- sub.w A0,A0
- rts
-.L3:
- mov.w #2,A0
-.L5:
- rts
- .end
-#endif
-#endif /* L_ucmpsi2 */
-
-#ifdef L_divhi3
-
-;; HImode divides for the H8/300.
-;; We bunch all of this into one object file since there are several
-;; "supporting routines".
-
-; general purpose normalize routine
-;
-; divisor in A0
-; dividend in A1
-; turns both into +ve numbers, and leaves what the answer sign
-; should be in A2L
-
-#ifdef __H8300__
- .section .text
- .align 2
-divnorm:
- mov.b #0x0,A2L
- or A0H,A0H ; is divisor > 0
- bge _lab1
- not A0H ; no - then make it +ve
- not A0L
- adds #1,A0
- xor #0x1,A2L ; and remember that in A2L
-_lab1: or A1H,A1H ; look at dividend
- bge _lab2
- not A1H ; it is -ve, make it positive
- not A1L
- adds #1,A1
- xor #0x1,A2L; and toggle sign of result
-_lab2: rts
-
-; A0=A0/A1 signed
-
- .global ___divhi3
-___divhi3:
- bsr divnorm
- bsr ___udivhi3
-negans: or A2L,A2L ; should answer be negative ?
- beq _lab4
- not A0H ; yes, so make it so
- not A0L
- adds #1,A0
-_lab4: rts
-
-; A0=A0%A1 signed
-
- .global ___modhi3
-___modhi3:
- bsr divnorm
- bsr ___udivhi3
- mov A3,A0
- bra negans
-
-; A0=A0%A1 unsigned
-
- .global ___umodhi3
-___umodhi3:
- bsr ___udivhi3
- mov A3,A0
- rts
-
-; A0=A0/A1 unsigned
-; A3=A0%A1 unsigned
-; A2H trashed
-; D high 8 bits of denom
-; d low 8 bits of denom
-; N high 8 bits of num
-; n low 8 bits of num
-; M high 8 bits of mod
-; m low 8 bits of mod
-; Q high 8 bits of quot
-; q low 8 bits of quot
-; P preserve
-
-; The h8 only has a 16/8 bit divide, so we look at the incoming and
-; see how to partition up the expression.
-
- .global ___udivhi3
-___udivhi3:
- ; A0 A1 A2 A3
- ; Nn Dd P
- sub.w A3,A3 ; Nn Dd xP 00
- or A1H,A1H
- bne divlongway
- or A0H,A0H
- beq _lab6
-
-; we know that D == 0 and N is != 0
- mov.b A0H,A3L ; Nn Dd xP 0N
- divxu A1L,A3 ; MQ
- mov.b A3L,A0H ; Q
-; dealt with N, do n
-_lab6: mov.b A0L,A3L ; n
- divxu A1L,A3 ; mq
- mov.b A3L,A0L ; Qq
- mov.b A3H,A3L ; m
- mov.b #0x0,A3H ; Qq 0m
- rts
-
-; D != 0 - which means the denominator is
-; loop around to get the result.
-
-divlongway:
- mov.b A0H,A3L ; Nn Dd xP 0N
- mov.b #0x0,A0H ; high byte of answer has to be zero
- mov.b #0x8,A2H ; 8
-div8: add.b A0L,A0L ; n*=2
- rotxl A3L ; Make remainder bigger
- rotxl A3H
- sub.w A1,A3 ; Q-=N
- bhs setbit ; set a bit ?
- add.w A1,A3 ; no : too far , Q+=N
-
- dec A2H
- bne div8 ; next bit
- rts
-
-setbit: inc A0L ; do insert bit
- dec A2H
- bne div8 ; next bit
- rts
-
-#endif /* __H8300__ */
-#endif /* L_divhi3 */
-
-#ifdef L_divsi3
-
-;; 4 byte integer divides for the H8/300.
-;;
-;; We have one routine which does all the work and lots of
-;; little ones which prepare the args and massage the sign.
-;; We bunch all of this into one object file since there are several
-;; "supporting routines".
-
-#ifdef __H8300H__
- .h8300h
-#endif
-
- .section .text
- .align 2
-
-; Put abs SIs into r0/r1 and r2/r3, and leave a 1 in r6l with sign of rest.
-; This function is here to keep branch displacements small.
-
-#ifdef __H8300__
-
-divnorm:
- mov.b #0,S2L ; keep the sign in S2
- mov.b A0H,A0H ; is the numerator -ve
- bge postive
-
- ; negate arg
- not A0H
- not A1H
- not A0L
- not A1L
-
- add #1,A1L
- addx #0,A1H
- addx #0,A0H
- addx #0,A0L
-
- mov.b #1,S2L ; the sign will be -ve
-postive:
- mov.b A2H,A2H ; is the denominator -ve
- bge postive2
- not A2L
- not A2H
- not A3L
- not A3H
- add.b #1,A3L
- addx #0,A3H
- addx #0,A2L
- addx #0,A2H
- xor #1,S2L ; toggle result sign
-postive2:
- rts
-
-#else /* __H8300H__ */
-
-divnorm:
- mov.b #0,S2L ; keep the sign in S2
- mov.l A0P,A0P ; is the numerator -ve
- bge postive
-
- neg.l A0P ; negate arg
- mov.b #1,S2L ; the sign will be -ve
-
-postive:
- mov.l A1P,A1P ; is the denominator -ve
- bge postive2
-
- neg.l A1P ; negate arg
- xor.b #1,S2L ; toggle result sign
-
-postive2:
- rts
-
-#endif
-
-; numerator in A0/A1
-; denominator in A2/A3
- .global ___modsi3
-___modsi3:
- PUSHP S2P
- PUSHP S0P
- PUSHP S1P
-
- bsr divnorm
- bsr divmodsi4
-#ifdef __H8300__
- mov S0,A0
- mov S1,A1
-#else
- mov.l S0P,A0P
-#endif
- bra exitdiv
-
- .global ___udivsi3
-___udivsi3:
- PUSHP S2P
- PUSHP S0P
- PUSHP S1P
- mov.b #0,S2L ; keep sign low
- bsr divmodsi4
- bra exitdiv
-
- .global ___umodsi3
-___umodsi3:
- PUSHP S2P
- PUSHP S0P
- PUSHP S1P
- mov.b #0,S2L ; keep sign low
- bsr divmodsi4
-#ifdef __H8300__
- mov S0,A0
- mov S1,A1
-#else
- mov.l S0P,A0P
-#endif
- bra exitdiv
-
- .global ___divsi3
-___divsi3:
- PUSHP S2P
- PUSHP S0P
- PUSHP S1P
- jsr divnorm
- jsr divmodsi4
-
- ; examine what the sign should be
-exitdiv:
- POPP S1P
- POPP S0P
-
- or S2L,S2L
- beq reti
-
- ; should be -ve
-#ifdef __H8300__
- not A0H
- not A1H
- not A0L
- not A1L
-
- add #1,A1L
- addx #0,A1H
- addx #0,A0H
- addx #0,A0L
-#else /* __H8300H__ */
- neg.l A0P
-#endif
-
-reti:
- POPP S2P
- rts
-
- ; takes A0/A1 numerator (A0P for 300h)
- ; A2/A3 denominator (A1P for 300h)
- ; returns A0/A1 quotient (A0P for 300h)
- ; S0/S1 remainder (S0P for 300h)
- ; trashes S2
-
-#ifdef __H8300__
-
-divmodsi4:
- sub.w S0,S0 ; zero play area
- mov.w S0,S1
- mov.b A2H,S2H
- or A2L,S2H
- or A3H,S2H
- bne DenHighZero
- mov.b A0H,A0H
- bne NumByte0Zero
- mov.b A0L,A0L
- bne NumByte1Zero
- mov.b A1H,A1H
- bne NumByte2Zero
- bra NumByte3Zero
-NumByte0Zero:
- mov.b A0H,S1L
- divxu A3L,S1
- mov.b S1L,A0H
-NumByte1Zero:
- mov.b A0L,S1L
- divxu A3L,S1
- mov.b S1L,A0L
-NumByte2Zero:
- mov.b A1H,S1L
- divxu A3L,S1
- mov.b S1L,A1H
-NumByte3Zero:
- mov.b A1L,S1L
- divxu A3L,S1
- mov.b S1L,A1L
-
- mov.b S1H,S1L
- mov.b #0x0,S1H
- rts
-
-; have to do the divide by shift and test
-DenHighZero:
- mov.b A0H,S1L
- mov.b A0L,A0H
- mov.b A1H,A0L
- mov.b A1L,A1H
-
- mov.b #0,A1L
- mov.b #24,S2H ; only do 24 iterations
-
-nextbit:
- add.w A1,A1 ; double the answer guess
- rotxl A0L
- rotxl A0H
-
- rotxl S1L ; double remainder
- rotxl S1H
- rotxl S0L
- rotxl S0H
- sub.w A3,S1 ; does it all fit
- subx A2L,S0L
- subx A2H,S0H
- bhs setone
-
- add.w A3,S1 ; no, restore mistake
- addx A2L,S0L
- addx A2H,S0H
-
- dec S2H
- bne nextbit
- rts
-
-setone:
- inc A1L
- dec S2H
- bne nextbit
- rts
-
-#else /* __H8300H__ */
-
-divmodsi4:
- sub.l S0P,S0P ; zero play area
- mov.w A1E,A1E ; denominator top word 0?
- bne DenHighZero
-
- ; do it the easy way, see page 107 in manual
- mov.w A0E,A2
- extu.l A2P
- divxu.w A1,A2P
- mov.w A2E,A0E
- divxu.w A1,A0P
- mov.w A0E,S0
- mov.w A2,A0E
- extu.l S0P
- rts
-
-DenHighZero:
- mov.w A0E,A2
- mov.b A2H,S0L
- mov.b A2L,A2H
- mov.b A0H,A2L
- mov.w A2,A0E
- mov.b A0L,A0H
- mov.b #0,A0L
- mov.b #24,S2H ; only do 24 iterations
-
-nextbit:
- shll.l A0P ; double the answer guess
- rotxl.l S0P ; double remainder
- sub.l A1P,S0P ; does it all fit?
- bhs setone
-
- add.l A1P,S0P ; no, restore mistake
- dec S2H
- bne nextbit
- rts
-
-setone:
- inc A0L
- dec S2H
- bne nextbit
- rts
-
-#endif
-#endif /* L_divsi3 */
-
-#ifdef L_mulhi3
-
-;; HImode multiply.
-; The h8 only has an 8*8->16 multiply.
-; The answer is the same as:
-;
-; product = (srca.l * srcb.l) + ((srca.h * srcb.l) + (srcb.h * srca.l)) * 256
-; (we can ignore A1.h * A0.h cause that will all off the top)
-; A0 in
-; A1 in
-; A0 answer
-
-#ifdef __H8300__
- .section .text
- .align 2
- .global ___mulhi3
-___mulhi3:
- mov.b A1L,A2L ; A2l gets srcb.l
- mulxu A0L,A2 ; A2 gets first sub product
-
- mov.b A0H,A3L ; prepare for
- mulxu A1L,A3 ; second sub product
-
- add.b A3L,A2H ; sum first two terms
-
- mov.b A1H,A3L ; third sub product
- mulxu A0L,A3
-
- add.b A3L,A2H ; almost there
- mov.w A2,A0 ; that is
- rts
-
-#endif
-#endif /* L_mulhi3 */
-
-#ifdef L_mulsi3
-
-;; SImode multiply.
-;;
-;; I think that shift and add may be sufficient for this. Using the
-;; supplied 8x8->16 would need 10 ops of 14 cycles each + overhead. This way
-;; the inner loop uses maybe 20 cycles + overhead, but terminates
-;; quickly on small args.
-;;
-;; A0/A1 src_a
-;; A2/A3 src_b
-;;
-;; while (a)
-;; {
-;; if (a & 1)
-;; r += b;
-;; a >>= 1;
-;; b <<= 1;
-;; }
-
- .section .text
- .align 2
-
-#ifdef __H8300__
-
- .global ___mulsi3
-___mulsi3:
- PUSHP S0P
- PUSHP S1P
- PUSHP S2P
-
- sub.w S0,S0
- sub.w S1,S1
-
- ; while (a)
-_top: mov.w A0,A0
- bne _more
- mov.w A1,A1
- beq _done
-_more: ; if (a & 1)
- bld #0,A1L
- bcc _nobit
- ; r += b
- add.w A3,S1
- addx A2L,S0L
- addx A2H,S0H
-_nobit:
- ; a >>= 1
- shlr A0H
- rotxr A0L
- rotxr A1H
- rotxr A1L
-
- ; b <<= 1
- add.w A3,A3
- addx A2L,A2L
- addx A2H,A2H
- bra _top
-
-_done:
- mov.w S0,A0
- mov.w S1,A1
- POPP S2P
- POPP S1P
- POPP S0P
- rts
-
-#else /* __H8300H__ */
-
- .h8300h
-
- .global ___mulsi3
-___mulsi3:
- sub.l A2P,A2P
-
- ; while (a)
-_top: mov.l A0P,A0P
- beq _done
-
- ; if (a & 1)
- bld #0,A0L
- bcc _nobit
-
- ; r += b
- add.l A1P,A2P
-
-_nobit:
- ; a >>= 1
- shlr.l A0P
-
- ; b <<= 1
- shll.l A1P
- bra _top
-
-_done:
- mov.l A2P,A0P
- rts
-
-#endif
-#endif /* L_mulsi3 */