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-rw-r--r--arch/metag/lib/memcpy.S185
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diff --git a/arch/metag/lib/memcpy.S b/arch/metag/lib/memcpy.S
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+! Copyright (C) 2008-2012 Imagination Technologies Ltd.
+
+ .text
+ .global _memcpy
+ .type _memcpy,function
+! D1Ar1 dst
+! D0Ar2 src
+! D1Ar3 cnt
+! D0Re0 dst
+_memcpy:
+ CMP D1Ar3, #16
+ MOV A1.2, D0Ar2 ! source pointer
+ MOV A0.2, D1Ar1 ! destination pointer
+ MOV A0.3, D1Ar1 ! for return value
+! If there are less than 16 bytes to copy use the byte copy loop
+ BGE $Llong_copy
+
+$Lbyte_copy:
+! Simply copy a byte at a time
+ SUBS TXRPT, D1Ar3, #1
+ BLT $Lend
+$Lloop_byte:
+ GETB D1Re0, [A1.2++]
+ SETB [A0.2++], D1Re0
+ BR $Lloop_byte
+
+$Lend:
+! Finally set return value and return
+ MOV D0Re0, A0.3
+ MOV PC, D1RtP
+
+$Llong_copy:
+ ANDS D1Ar5, D1Ar1, #7 ! test destination alignment
+ BZ $Laligned_dst
+
+! The destination address is not 8 byte aligned. We will copy bytes from
+! the source to the destination until the remaining data has an 8 byte
+! destination address alignment (i.e we should never copy more than 7
+! bytes here).
+$Lalign_dst:
+ GETB D0Re0, [A1.2++]
+ ADD D1Ar5, D1Ar5, #1 ! dest is aligned when D1Ar5 reaches #8
+ SUB D1Ar3, D1Ar3, #1 ! decrement count of remaining bytes
+ SETB [A0.2++], D0Re0
+ CMP D1Ar5, #8
+ BNE $Lalign_dst
+
+! We have at least (16 - 7) = 9 bytes to copy - calculate the number of 8 byte
+! blocks, then jump to the unaligned copy loop or fall through to the aligned
+! copy loop as appropriate.
+$Laligned_dst:
+ MOV D0Ar4, A1.2
+ LSR D1Ar5, D1Ar3, #3 ! D1Ar5 = number of 8 byte blocks
+ ANDS D0Ar4, D0Ar4, #7 ! test source alignment
+ BNZ $Lunaligned_copy ! if unaligned, use unaligned copy loop
+
+! Both source and destination are 8 byte aligned - the easy case.
+$Laligned_copy:
+ LSRS D1Ar5, D1Ar3, #5 ! D1Ar5 = number of 32 byte blocks
+ BZ $Lbyte_copy
+ SUB TXRPT, D1Ar5, #1
+
+$Laligned_32:
+ GETL D0Re0, D1Re0, [A1.2++]
+ GETL D0Ar6, D1Ar5, [A1.2++]
+ SETL [A0.2++], D0Re0, D1Re0
+ SETL [A0.2++], D0Ar6, D1Ar5
+ GETL D0Re0, D1Re0, [A1.2++]
+ GETL D0Ar6, D1Ar5, [A1.2++]
+ SETL [A0.2++], D0Re0, D1Re0
+ SETL [A0.2++], D0Ar6, D1Ar5
+ BR $Laligned_32
+
+! If there are any remaining bytes use the byte copy loop, otherwise we are done
+ ANDS D1Ar3, D1Ar3, #0x1f
+ BNZ $Lbyte_copy
+ B $Lend
+
+! The destination is 8 byte aligned but the source is not, and there are 8
+! or more bytes to be copied.
+$Lunaligned_copy:
+! Adjust the source pointer (A1.2) to the 8 byte boundary before its
+! current value
+ MOV D0Ar4, A1.2
+ MOV D0Ar6, A1.2
+ ANDMB D0Ar4, D0Ar4, #0xfff8
+ MOV A1.2, D0Ar4
+! Save the number of bytes of mis-alignment in D0Ar4 for use later
+ SUBS D0Ar6, D0Ar6, D0Ar4
+ MOV D0Ar4, D0Ar6
+! if there is no mis-alignment after all, use the aligned copy loop
+ BZ $Laligned_copy
+
+! prefetch 8 bytes
+ GETL D0Re0, D1Re0, [A1.2]
+
+ SUB TXRPT, D1Ar5, #1
+
+! There are 3 mis-alignment cases to be considered. Less than 4 bytes, exactly
+! 4 bytes, and more than 4 bytes.
+ CMP D0Ar6, #4
+ BLT $Lunaligned_1_2_3 ! use 1-3 byte mis-alignment loop
+ BZ $Lunaligned_4 ! use 4 byte mis-alignment loop
+
+! The mis-alignment is more than 4 bytes
+$Lunaligned_5_6_7:
+ SUB D0Ar6, D0Ar6, #4
+! Calculate the bit offsets required for the shift operations necesssary
+! to align the data.
+! D0Ar6 = bit offset, D1Ar5 = (32 - bit offset)
+ MULW D0Ar6, D0Ar6, #8
+ MOV D1Ar5, #32
+ SUB D1Ar5, D1Ar5, D0Ar6
+! Move data 4 bytes before we enter the main loop
+ MOV D0Re0, D1Re0
+
+$Lloop_5_6_7:
+ GETL D0Ar2, D1Ar1, [++A1.2]
+! form 64-bit data in D0Re0, D1Re0
+ LSR D0Re0, D0Re0, D0Ar6
+ MOV D1Re0, D0Ar2
+ LSL D1Re0, D1Re0, D1Ar5
+ ADD D0Re0, D0Re0, D1Re0
+
+ LSR D0Ar2, D0Ar2, D0Ar6
+ LSL D1Re0, D1Ar1, D1Ar5
+ ADD D1Re0, D1Re0, D0Ar2
+
+ SETL [A0.2++], D0Re0, D1Re0
+ MOV D0Re0, D1Ar1
+ BR $Lloop_5_6_7
+
+ B $Lunaligned_end
+
+$Lunaligned_1_2_3:
+! Calculate the bit offsets required for the shift operations necesssary
+! to align the data.
+! D0Ar6 = bit offset, D1Ar5 = (32 - bit offset)
+ MULW D0Ar6, D0Ar6, #8
+ MOV D1Ar5, #32
+ SUB D1Ar5, D1Ar5, D0Ar6
+
+$Lloop_1_2_3:
+! form 64-bit data in D0Re0,D1Re0
+ LSR D0Re0, D0Re0, D0Ar6
+ LSL D1Ar1, D1Re0, D1Ar5
+ ADD D0Re0, D0Re0, D1Ar1
+ MOV D0Ar2, D1Re0
+ LSR D0FrT, D0Ar2, D0Ar6
+ GETL D0Ar2, D1Ar1, [++A1.2]
+
+ MOV D1Re0, D0Ar2
+ LSL D1Re0, D1Re0, D1Ar5
+ ADD D1Re0, D1Re0, D0FrT
+
+ SETL [A0.2++], D0Re0, D1Re0
+ MOV D0Re0, D0Ar2
+ MOV D1Re0, D1Ar1
+ BR $Lloop_1_2_3
+
+ B $Lunaligned_end
+
+! The 4 byte mis-alignment case - this does not require any shifting, just a
+! shuffling of registers.
+$Lunaligned_4:
+ MOV D0Re0, D1Re0
+$Lloop_4:
+ GETL D0Ar2, D1Ar1, [++A1.2]
+ MOV D1Re0, D0Ar2
+ SETL [A0.2++], D0Re0, D1Re0
+ MOV D0Re0, D1Ar1
+ BR $Lloop_4
+
+$Lunaligned_end:
+! If there are no remaining bytes to copy, we are done.
+ ANDS D1Ar3, D1Ar3, #7
+ BZ $Lend
+! Re-adjust the source pointer (A1.2) back to the actual (unaligned) byte
+! address of the remaining bytes, and fall through to the byte copy loop.
+ MOV D0Ar6, A1.2
+ ADD D1Ar5, D0Ar4, D0Ar6
+ MOV A1.2, D1Ar5
+ B $Lbyte_copy
+
+ .size _memcpy,.-_memcpy