diff options
author | jason <jason@8a072113-8704-0410-8d35-dd094bca7971> | 2008-10-28 01:38:50 +0000 |
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committer | jason <jason@8a072113-8704-0410-8d35-dd094bca7971> | 2008-10-28 01:38:50 +0000 |
commit | baba851215b44ac3b60b9248eb02bcce7eb76247 (patch) | |
tree | 8c0f5c006875532a30d4409f5e94b0f310ff00a7 /SRC/sptrfs.f |
Move LAPACK trunk into position.
Diffstat (limited to 'SRC/sptrfs.f')
-rw-r--r-- | SRC/sptrfs.f | 301 |
1 files changed, 301 insertions, 0 deletions
diff --git a/SRC/sptrfs.f b/SRC/sptrfs.f new file mode 100644 index 00000000..d7241dd5 --- /dev/null +++ b/SRC/sptrfs.f @@ -0,0 +1,301 @@ + SUBROUTINE SPTRFS( N, NRHS, D, E, DF, EF, B, LDB, X, LDX, FERR, + $ BERR, WORK, INFO ) +* +* -- LAPACK routine (version 3.1) -- +* Univ. of Tennessee, Univ. of California Berkeley and NAG Ltd.. +* November 2006 +* +* .. Scalar Arguments .. + INTEGER INFO, LDB, LDX, N, NRHS +* .. +* .. Array Arguments .. + REAL B( LDB, * ), BERR( * ), D( * ), DF( * ), + $ E( * ), EF( * ), FERR( * ), WORK( * ), + $ X( LDX, * ) +* .. +* +* Purpose +* ======= +* +* SPTRFS improves the computed solution to a system of linear +* equations when the coefficient matrix is symmetric positive definite +* and tridiagonal, and provides error bounds and backward error +* estimates for the solution. +* +* Arguments +* ========= +* +* N (input) INTEGER +* The order of the matrix A. N >= 0. +* +* NRHS (input) INTEGER +* The number of right hand sides, i.e., the number of columns +* of the matrix B. NRHS >= 0. +* +* D (input) REAL array, dimension (N) +* The n diagonal elements of the tridiagonal matrix A. +* +* E (input) REAL array, dimension (N-1) +* The (n-1) subdiagonal elements of the tridiagonal matrix A. +* +* DF (input) REAL array, dimension (N) +* The n diagonal elements of the diagonal matrix D from the +* factorization computed by SPTTRF. +* +* EF (input) REAL array, dimension (N-1) +* The (n-1) subdiagonal elements of the unit bidiagonal factor +* L from the factorization computed by SPTTRF. +* +* B (input) REAL array, dimension (LDB,NRHS) +* The right hand side matrix B. +* +* LDB (input) INTEGER +* The leading dimension of the array B. LDB >= max(1,N). +* +* X (input/output) REAL array, dimension (LDX,NRHS) +* On entry, the solution matrix X, as computed by SPTTRS. +* On exit, the improved solution matrix X. +* +* LDX (input) INTEGER +* The leading dimension of the array X. LDX >= max(1,N). +* +* FERR (output) REAL array, dimension (NRHS) +* The forward error bound for each solution vector +* X(j) (the j-th column of the solution matrix X). +* If XTRUE is the true solution corresponding to X(j), FERR(j) +* is an estimated upper bound for the magnitude of the largest +* element in (X(j) - XTRUE) divided by the magnitude of the +* largest element in X(j). +* +* BERR (output) REAL array, dimension (NRHS) +* The componentwise relative backward error of each solution +* vector X(j) (i.e., the smallest relative change in +* any element of A or B that makes X(j) an exact solution). +* +* WORK (workspace) REAL array, dimension (2*N) +* +* INFO (output) INTEGER +* = 0: successful exit +* < 0: if INFO = -i, the i-th argument had an illegal value +* +* Internal Parameters +* =================== +* +* ITMAX is the maximum number of steps of iterative refinement. +* +* ===================================================================== +* +* .. Parameters .. + INTEGER ITMAX + PARAMETER ( ITMAX = 5 ) + REAL ZERO + PARAMETER ( ZERO = 0.0E+0 ) + REAL ONE + PARAMETER ( ONE = 1.0E+0 ) + REAL TWO + PARAMETER ( TWO = 2.0E+0 ) + REAL THREE + PARAMETER ( THREE = 3.0E+0 ) +* .. +* .. Local Scalars .. + INTEGER COUNT, I, IX, J, NZ + REAL BI, CX, DX, EPS, EX, LSTRES, S, SAFE1, SAFE2, + $ SAFMIN +* .. +* .. External Subroutines .. + EXTERNAL SAXPY, SPTTRS, XERBLA +* .. +* .. Intrinsic Functions .. + INTRINSIC ABS, MAX +* .. +* .. External Functions .. + INTEGER ISAMAX + REAL SLAMCH + EXTERNAL ISAMAX, SLAMCH +* .. +* .. Executable Statements .. +* +* Test the input parameters. +* + INFO = 0 + IF( N.LT.0 ) THEN + INFO = -1 + ELSE IF( NRHS.LT.0 ) THEN + INFO = -2 + ELSE IF( LDB.LT.MAX( 1, N ) ) THEN + INFO = -8 + ELSE IF( LDX.LT.MAX( 1, N ) ) THEN + INFO = -10 + END IF + IF( INFO.NE.0 ) THEN + CALL XERBLA( 'SPTRFS', -INFO ) + RETURN + END IF +* +* Quick return if possible +* + IF( N.EQ.0 .OR. NRHS.EQ.0 ) THEN + DO 10 J = 1, NRHS + FERR( J ) = ZERO + BERR( J ) = ZERO + 10 CONTINUE + RETURN + END IF +* +* NZ = maximum number of nonzero elements in each row of A, plus 1 +* + NZ = 4 + EPS = SLAMCH( 'Epsilon' ) + SAFMIN = SLAMCH( 'Safe minimum' ) + SAFE1 = NZ*SAFMIN + SAFE2 = SAFE1 / EPS +* +* Do for each right hand side +* + DO 90 J = 1, NRHS +* + COUNT = 1 + LSTRES = THREE + 20 CONTINUE +* +* Loop until stopping criterion is satisfied. +* +* Compute residual R = B - A * X. Also compute +* abs(A)*abs(x) + abs(b) for use in the backward error bound. +* + IF( N.EQ.1 ) THEN + BI = B( 1, J ) + DX = D( 1 )*X( 1, J ) + WORK( N+1 ) = BI - DX + WORK( 1 ) = ABS( BI ) + ABS( DX ) + ELSE + BI = B( 1, J ) + DX = D( 1 )*X( 1, J ) + EX = E( 1 )*X( 2, J ) + WORK( N+1 ) = BI - DX - EX + WORK( 1 ) = ABS( BI ) + ABS( DX ) + ABS( EX ) + DO 30 I = 2, N - 1 + BI = B( I, J ) + CX = E( I-1 )*X( I-1, J ) + DX = D( I )*X( I, J ) + EX = E( I )*X( I+1, J ) + WORK( N+I ) = BI - CX - DX - EX + WORK( I ) = ABS( BI ) + ABS( CX ) + ABS( DX ) + ABS( EX ) + 30 CONTINUE + BI = B( N, J ) + CX = E( N-1 )*X( N-1, J ) + DX = D( N )*X( N, J ) + WORK( N+N ) = BI - CX - DX + WORK( N ) = ABS( BI ) + ABS( CX ) + ABS( DX ) + END IF +* +* Compute componentwise relative backward error from formula +* +* max(i) ( abs(R(i)) / ( abs(A)*abs(X) + abs(B) )(i) ) +* +* where abs(Z) is the componentwise absolute value of the matrix +* or vector Z. If the i-th component of the denominator is less +* than SAFE2, then SAFE1 is added to the i-th components of the +* numerator and denominator before dividing. +* + S = ZERO + DO 40 I = 1, N + IF( WORK( I ).GT.SAFE2 ) THEN + S = MAX( S, ABS( WORK( N+I ) ) / WORK( I ) ) + ELSE + S = MAX( S, ( ABS( WORK( N+I ) )+SAFE1 ) / + $ ( WORK( I )+SAFE1 ) ) + END IF + 40 CONTINUE + BERR( J ) = S +* +* Test stopping criterion. Continue iterating if +* 1) The residual BERR(J) is larger than machine epsilon, and +* 2) BERR(J) decreased by at least a factor of 2 during the +* last iteration, and +* 3) At most ITMAX iterations tried. +* + IF( BERR( J ).GT.EPS .AND. TWO*BERR( J ).LE.LSTRES .AND. + $ COUNT.LE.ITMAX ) THEN +* +* Update solution and try again. +* + CALL SPTTRS( N, 1, DF, EF, WORK( N+1 ), N, INFO ) + CALL SAXPY( N, ONE, WORK( N+1 ), 1, X( 1, J ), 1 ) + LSTRES = BERR( J ) + COUNT = COUNT + 1 + GO TO 20 + END IF +* +* Bound error from formula +* +* norm(X - XTRUE) / norm(X) .le. FERR = +* norm( abs(inv(A))* +* ( abs(R) + NZ*EPS*( abs(A)*abs(X)+abs(B) ))) / norm(X) +* +* where +* norm(Z) is the magnitude of the largest component of Z +* inv(A) is the inverse of A +* abs(Z) is the componentwise absolute value of the matrix or +* vector Z +* NZ is the maximum number of nonzeros in any row of A, plus 1 +* EPS is machine epsilon +* +* The i-th component of abs(R)+NZ*EPS*(abs(A)*abs(X)+abs(B)) +* is incremented by SAFE1 if the i-th component of +* abs(A)*abs(X) + abs(B) is less than SAFE2. +* + DO 50 I = 1, N + IF( WORK( I ).GT.SAFE2 ) THEN + WORK( I ) = ABS( WORK( N+I ) ) + NZ*EPS*WORK( I ) + ELSE + WORK( I ) = ABS( WORK( N+I ) ) + NZ*EPS*WORK( I ) + SAFE1 + END IF + 50 CONTINUE + IX = ISAMAX( N, WORK, 1 ) + FERR( J ) = WORK( IX ) +* +* Estimate the norm of inv(A). +* +* Solve M(A) * x = e, where M(A) = (m(i,j)) is given by +* +* m(i,j) = abs(A(i,j)), i = j, +* m(i,j) = -abs(A(i,j)), i .ne. j, +* +* and e = [ 1, 1, ..., 1 ]'. Note M(A) = M(L)*D*M(L)'. +* +* Solve M(L) * x = e. +* + WORK( 1 ) = ONE + DO 60 I = 2, N + WORK( I ) = ONE + WORK( I-1 )*ABS( EF( I-1 ) ) + 60 CONTINUE +* +* Solve D * M(L)' * x = b. +* + WORK( N ) = WORK( N ) / DF( N ) + DO 70 I = N - 1, 1, -1 + WORK( I ) = WORK( I ) / DF( I ) + WORK( I+1 )*ABS( EF( I ) ) + 70 CONTINUE +* +* Compute norm(inv(A)) = max(x(i)), 1<=i<=n. +* + IX = ISAMAX( N, WORK, 1 ) + FERR( J ) = FERR( J )*ABS( WORK( IX ) ) +* +* Normalize error. +* + LSTRES = ZERO + DO 80 I = 1, N + LSTRES = MAX( LSTRES, ABS( X( I, J ) ) ) + 80 CONTINUE + IF( LSTRES.NE.ZERO ) + $ FERR( J ) = FERR( J ) / LSTRES +* + 90 CONTINUE +* + RETURN +* +* End of SPTRFS +* + END |